Canadian Forces Aptitude Test (CFAT) Practice 2025 - Free CFAT Practice Questions and Study Guide

Question: 1 / 400

A box measuring 3 cm wide, 2 cm deep, and 4 cm high has all sides doubled in length. What is the total surface area of the larger box?

104 cm²

208 cm²

To determine the total surface area of the larger box after the dimensions have been doubled, we first need to calculate the original dimensions of the box, which are 3 cm wide, 2 cm deep, and 4 cm high.

When these dimensions are doubled, the new dimensions become:

- Width: \(3 \text{ cm} \times 2 = 6 \text{ cm}\)

- Depth: \(2 \text{ cm} \times 2 = 4 \text{ cm}\)

- Height: \(4 \text{ cm} \times 2 = 8 \text{ cm}\)

The formula for the total surface area of a rectangular box is given by:

\[

\text{Surface Area} = 2(w \cdot h + w \cdot d + h \cdot d)

\]

Substituting the new dimensions into this formula:

\[

\text{Surface Area} = 2(6 \cdot 8 + 6 \cdot 4 + 8 \cdot 4)

\]

Now, calculate each term:

- \(6 \cdot 8 = 48\)

- \(6 \cdot 4 =

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48 cm²

96 cm²

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